a+b+c=0 then prove that a2+b2+c2=3abc
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Hi ,
a + b + c = 0 ---( 1 )
***************
We know the algebraic identity ,
a³ + b³ + c³ = ( a+b+c)(a²+b²+c²-ab-bc-ca) + 3abc
*************************
From ( 1 ) ,
a³ + b³ + c³ = 0 + 3abc
a³ + b³ + c³ = 3abc
I hope this helps you.
: )
a + b + c = 0 ---( 1 )
***************
We know the algebraic identity ,
a³ + b³ + c³ = ( a+b+c)(a²+b²+c²-ab-bc-ca) + 3abc
*************************
From ( 1 ) ,
a³ + b³ + c³ = 0 + 3abc
a³ + b³ + c³ = 3abc
I hope this helps you.
: )
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