Question

a+b+c=0 ; then value of a²+b²+c²/(bc+ca+ab)=?

Answer 1

(A+b+c)^2=a^2+b^2+c^2+2 (ab+bc+ca)
0=a^2 +b^2+c^2+2 (ab+bc+ca)
A^2+b^2+c^2= -2 (ab+bc+ca)
A^2+b^2+c^2/(ab+bc+ca)= -2

Answer 2

Answer:

Step-by-step explanation:

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