a + b + C = 12 ab + bc + ac = 15 find the value of a square + b square + c square
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a+b+c = 12
squaring both sides we get
(a+b+c)² = 144
let a+b = x
(x+c)² = 144
x² + c² + 2cx = 144
Now put the value of x in the above equation
(a+b)² + c² + 2c(a+b) = 144
After solving we get:
a²+b²+c² + 2ab + 2bc + 2ca = 144
a²+b²+c² = 144 - (2ab + 2bc + 2ca)........................................eq1
We know ab+bc+ca = 15
multiply above eq by 2 ,we get
2ab+2bc+2ca=30
Putting this in eq1, we get
a²+b²+c² = 114
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