Math, asked by pelangovan517, 4 months ago

(a+b-c)2 is equal to​

Answers

Answered by ELECTROBRAINY
0

Answer:

(a+b-c)^2

Can be expressed as

=(a+b-c)*(a+b-c)

On expansion of the above expression

=a*(a+b-c)+b*(a+b-c)-c*(a+b-c)

=a^2+ab-ac+ba+b^2-bc-ca-cb+c^2

Rearrange the above equation

=a^2+b^2+c^2+ab+ba-ac-ca-bc-cb

Rearrange by commutative property

=a^2+b^2+c^2+ab+ab-ac-ac-bc-bc

=a^2+b^2+c^2+2ab-2ac-2bc

On taking out the common terms, the expansion results in the final answer

=a^2+b^2+c^2+2(ab-ac-bc)

Step-by-step explanation:

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Answered by Anonymous
1

Step-by-step explanation:

(a + b + c) {}^{2}  =  \\ a {}^{2}  + b {}^{2}  + c {}^{2}  + 2ab + 2bc + 2ca

I hope it helps you Mark me as brainlist please please please.............

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