Question

A, B, C do a work in 10, 15 and 7 days respectively. A and B start the work and A leaves after 5 days. Then C join B in how many days will the remaining work now be completed?

Answer 1

Hey Dear,

◆ Answer -

35/44 day

◆ Explanation -

Given that A, B and C do a work in 10, 15 and 7 days respectively. So A, B and C can do 1/10th, 1/15th and 1/7th work in one day.

In 5 days, part of work completed is -

Work completed = 5 × 1/10 + 5 × 1/15

Work completed = 5/6 th work

Remaining 1/6th work is completed by B and C in x days.

Remaining work = x × 1/15 + x × 1/7

1 - 5/6 = x × 22/105

x = 1/6 × 105/22

x = 35/44 day

Therefore, 35/44 day are required to complete remaining work.

Hope that solved your query...