Question

A rod AB is
A rod AB is shown in figure. End A of the rod is fixed on the ground. Block is m
3 m/s towards right. The velocity of end B of rod when rod makes an ang
of the rod is fixed on the ground. Block is moving with velocity
velocity of end B of rod when rod makes an angle of 60° with the ground is:​

Answer 1

Answer:

Explanation:

The end B will do circular motion ..so it's velocity vector will become as shown in given image

Answer 2

Answer:

The velocity of end B of rod is 2√3 m/s.

(c) is correct option.

Explanation:

Given that,

Velocity of block = √3 m/s

Angle = 60°

We need to calculate the velocity of end B of rod

Using velocity component

$v\sin\theta=\sqrty{3}$

$v\sin30=\sqrt{3}$

$v=\dfrac{\sqrt{3}}{\sin30}$

$v=2\sqrt{3}\ m/s$

Hence, The velocity of end B of rod is 2√3 m/s.