Question

A baby of mass 500g is moving with 54 km/h comes to rest 6 sec. Then force acting on it

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Answer 1

$\huge \fbox \red{\fbox{Answer}}$

$\large \bf{Given:}$

$\sf \mapsto{Mass \: of \: baby(m)=500g= \frac{500}{1000} kg = 0.5kg}$

$\sf \mapsto{Initial \: velocity(u)=54km/h=54 \times \frac{5}{18} m/s = 15m/s}$

$\sf \mapsto{Time \: taken(t)=6sec}$

$\large \bf{To \: find:}$

$\sf \leadsto{Force \: acting \: on \: baby. }$

$\large \bf{Concept \: used:}$

$\sf \rightarrow{Final \: velocity(v) \: of \: baby \: is \: 0m/s.}$

$\large \bf{Formula \: used:}$

$\boxed {\bf{Acceleration \: of \: baby(a) = \frac{Final \: velocity - Initial \: velocity}{Time} = \frac{v - u}{t} }}$

$\boxed {\bf{Force=Mass×Acceleration = ma}}$

$\large \bf{According \: to \: Question:}$

$\sf \implies{Acceleration \: of \: baby(a) = \frac{Final \: velocity - Initial \: velocity}{Time} = \frac{v - u}{t} }$

$\sf \implies{Acceleration \: of \: baby(a) = \frac{0- 15}{6} = \frac{- 15}{6} = - 2.5m/ {s}^{2} }$

$\bf{Then,}$

$\sf \implies{Force=Mass×Acceleration}$

$\sf \implies{Force=0.5×2.5=1.25N}$

$\bf{Hence, Force \: acting \: on \: baby \: is \: 1.25 \: newton.}$

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Answer 2

Answer:

1.25 Newton

Explanation:

Given:-

• Mass ,m = 500g = 0.5 Kg
• Initial velocity ,u = 54km/h = 54×5/18 = 15 m/s

• Final Velocity ,v = 0m/s

• Time taken ,t = 6 s

To Find:-

• Force ,F

Solution:-

Firstly we calculate the acceleration of the body. Acceleration is defined as the rate of change of velocity at per unit time.

• a = v-u/t

where

v is the final velocity

a is the acceleration

u is the initial velocity

t is the time taken

Substitute the value we get

→ a = 0-15/6

→ a = -15/6

→ a = -5/2

→ a = -2.5m/s²

Here, negative sign show retardation .

Acceleration of the body is 2.5m/s²

As we know that Force is defined as the product of mass and acceleration

• F = ma

Substitute the value we get

→ F = 0.5×2.5

→ F = 1.25 N

Hence, the Force acting on it is 1.25 Newton.