A bag contained 105kg 690gm of wheat. There was a consumption of 35kg 450gm, 27kg 360gm, 37kg 880gm during 3 months. How much wheat remains in the bag? please somebody can give me the answer
Answers
Answer:
5 kg wheat
Step-by-step explanation:
We know, 1 kg = 1000 gm
Initially the bag contained = (105×1000)+690 gm wheat
= 105000+690 gm wheat
= 105690 gm wheat
Wheat consumed in 3 months = {(35×1000)+450} + {(27×1000)+360} + {(37×1000)+880} gm wheat
= (35450+27360+37880) gm wheat
= 100690 gm wheat
So, remaining wheat = (105690-100690) gm
= 5000 gm wheat
= 5 kg wheat
Answer:
Given;
total weight of wheat bag contain = 105kg 690gm
use in first month = 35kg 450gm
use in second month. = 27kg 360gm
use in third month. = 37kg 880gm
total wheat use in three months = sum of use of first month, second month and third month
35kg 450gm + 27kg 360gm + 37kg 880gm
= 100kg 690 gm
Total wheat remain in the bag = total weight of wheat bag - total weight use in three month
105kg 690gm - 100kg 690gm = 5kg
therefore 5kg wheat remain in bag.
( l hope it will help you, Thankyou)