Question

A bag contains 18 balls out of which X balls are red if one ball is drawn at random from the bag what is the probability that it is not red .if 2 more red balls are put in the bag the probability of drawing a red ball with will be 9 /8 times the probability of drawing a red ball is the first case find the value of x

Answer 1

Total No . of Obs = 18

No . of Red Balls = x

Probability of Red Ball = Favourable Obs / Total No. of Obs

P(of Red Ball) = x/18

Two Red Balls Are Added

So,

No . of Red Balls = x + 2

Total no .of Balls = 18 + 2 = 20

P(of red Ball) = x + 2 / 20

P given 9 times of P obtained in A

9/8 * x/18 = (x + 2)/20

x / 16 = (x + 2)/20

(x / 16) *  20 = x + 2

5x / 4 = x + 2

5x = 4x + 8

5x - 4x = 8

x = 8

Therefore,

Initial No.Of Red Balls = 8

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