Question

A bag contains 2 yellow 3 green and 2 blue balls.Two balls are drwan at random.What is the probability that none of the balls drawn are blue?

Answer 1

let the event of getting no blue ball be A

n(A)=5

T(s)=7

P(A)=5/7

Answer 2

Answer:

Total outcomes =2(Yellow) +3(Green) +2 (Blue) = 7

Probablity for getting none of the blue ball

= subtract the blue balls from the given data

=2+3+2. = 7

=7-2 =5

P( getting none of the blue ball)

The subtracted data / total. outcomes

Therefore, =5/7