A bag contains 25 balls numbered 1 through 25. Suppose an odd number is considered a ‘Success’. Two balls are drawn from the bag with replacement. Find the probability of getting a. Two successes b. exactly one success c. at least one success d. no successes
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Given A bag contains 25 balls numbered 1 through 25. Suppose an odd number is considered a ‘Success’. Two balls are drawn from the bag with replacement. Find the probability of getting a. Two successes b. exactly one success c. at least one success d. no successes
- We have odd numbers from 1 to 25 will be 1,3,5,7,9,11,13,15,17,19,21,23,25
- Now from 1 to 25 there are 13 odd and 12 even numbers.
- So P (two successes) = 13/25 x 13/25
- = 169 / 625
- So P(exactly one success) = 13/25 x 12/25 + 12/25 x 13/25
- = 156 /625 + 156/625
- = 312 / 625
- So P (at least one success) = 1 – P (no success)
- = 1 – 12/25 x 12/25
- = 1 - 144/625
- = 481 / 625
- So P (No success) = 12/25 x 12/25
- = 144 / 625
Reference link will be
https://brainly.in/question/21369591
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