A bag contains 3 red, 4 green and 2 black balls. two balls are drawn at random. find the probability of the same colour
Answers
Answered by
0
Final Answer : 5/18
Steps:
1) Total no. of ways to select randomly any two balls is (3+4+2) C (2) = 9C(2) = 36
2) To select Two balls of same colour :
Red + Green + Black
=> 3C(2) + 4C(2) + 2C(2)
=> 3 + 6 + 1
=> 10.
H^nce,
Probabability that both balls are of sane color 1
=> 10/36 = 5/18
Steps:
1) Total no. of ways to select randomly any two balls is (3+4+2) C (2) = 9C(2) = 36
2) To select Two balls of same colour :
Red + Green + Black
=> 3C(2) + 4C(2) + 2C(2)
=> 3 + 6 + 1
=> 10.
H^nce,
Probabability that both balls are of sane color 1
=> 10/36 = 5/18
Answered by
0
Total outcomes = 9
Favourable outcomes = 8 (2 red balls, 4 green balls, 2 black balls)
Probability = Favourable outcomes / total outcomes
P ( E) = 8/9
Favourable outcomes = 8 (2 red balls, 4 green balls, 2 black balls)
Probability = Favourable outcomes / total outcomes
P ( E) = 8/9
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