Question

A bag contains 3 red,4 green and 2 blue balls.Two balls are drawn at random.What is the probability that none of the balls drawn is blue

Answer 1

total outcomes = 9 balls

no of balls without blue balls 9-2=7

now ,favourable outcomes =7/9

Answer 2

Probability = Number of favourable outcomes / Number of total outcomes .

No. Of red balls = 3

No. Of green balls = 4

No. Of blue balls = 2

No . Total balls ( outcomes ) = 9

P= 7/ 9