A bag contains 4 pink and 5 blue beads. another bag contains 3 pink and 6 blue beads. two beads are drawn, one from each bag. find the probability that one is pink and the other is blue.
Answers
Answered by
0
17/27 is correct answer
Answered by
0
Bag A:
Pink =4
Blue=5
Total=9
Bag B:
Pink=3
Blue=6
Total=9
Two beads drawn 1 from each bag,This can be done in 9c1×9c1 =9×9=81 ways.
Now,
There are 2 ways to get 1 blue and 1 pink .
Either I pick a pink from Bag A and a Blue from Bag B which can be done in 4c1×6c1=4×6=24 ways.
Or I pick a blue from Bag A and a Pink from Bag B which can be done in 5c1×3c1=5×3=15.
Hence Total ways of performing the task =24+15
=39 ways.
Hence,Required Probability = 39/81=13/27.
Hope it helps.
Pink =4
Blue=5
Total=9
Bag B:
Pink=3
Blue=6
Total=9
Two beads drawn 1 from each bag,This can be done in 9c1×9c1 =9×9=81 ways.
Now,
There are 2 ways to get 1 blue and 1 pink .
Either I pick a pink from Bag A and a Blue from Bag B which can be done in 4c1×6c1=4×6=24 ways.
Or I pick a blue from Bag A and a Pink from Bag B which can be done in 5c1×3c1=5×3=15.
Hence Total ways of performing the task =24+15
=39 ways.
Hence,Required Probability = 39/81=13/27.
Hope it helps.
Similar questions