Question

A bag contains 5 red and 8 black balls and another bag contains 3 red and 6 black balls. A
ball is drawn from each bag. What is the probability that one is red and the other is black?​

Answer 1

Answer:

p(drawn ball is red from bag :1)=5/13

p(drawn ball is black from bag:1)=8/13

p(drawn ball is red in bag:2)=3/9

p(ball drawn is black in bag:2)=6/9

Step-by-step explanation:

in bag one there are totally 13 balls out of which 5 are red..since there are 5 red balls in 13 balls the chance of getting red ball is 5/13

the remaining no of balls in bag :1 are 8 other than red balls so chance of getting black ball is 8/13

in bag 2 there are totally 9 balls out of which 3 are red..so chance of getting red ball are 3/9..

and chance to get black ball is 6/9

Answer 2

Step-by-step explanation:

total no of balls in first bag = 5+8=13

now ,

P(a red ball ) = 5/13

P(a black ball)=8/13

total no. of balls in second bag = 6+3=9

now,

P(a red ball)= 3/9=1/3

P(a black ball)=6/9=2/3