A bag contains 50 p, 25 p and 10 p coins in the ratio 5: 9: 4, amounting to rs. 206. Find the number of coins of each type respectively. * 1 point 360, 160, 200 160, 360, 200 200, 360,160 200,160,300
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1 rupees = 100 paise
1 paise is equal to 1 by hundred rupees
50 paise is equal to 50 /100 rupees
so , One by Two Rupees
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No. of 5O,25,10 rupees coin =5x,9x,4x respct.
0.50×5x+0.25×9x+0.1×4x= 206(1 RS =100P)
From it find value of x and put the value of x in 5x,9x,4x and find the NO. of coin
0.50×5x+0.25×9x+0.1×4x= 206(1 RS =100P)
From it find value of x and put the value of x in 5x,9x,4x and find the NO. of coin
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