A bag contains 50 p,25p,and 10p coins in ratio 5:9:4, amounting to RS .206 .find the no.of coins of each type
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Let the number of coins be 50p , 25p and 10p coins be 5x , 9x and 4x
Rupees 206 = 20600p
A.T.Q. -
5x(50) + 9x(25) + 4x(10) = 20600
or, 250x + 225x + 40x = 20600
or, 515x = 20600
or, x = 20600/515
or, x = 40
No. of 50p coins = 5x = 5×40 = 200coins
No. of 25p coins = 9x = 9×40 = 360coins
No. of 10p coins = 4x = 4 × 40 = 160 coins
Answer) No. of 50p coins is 200 , 25p coins
is 360 and 10p coins is 160.
Rupees 206 = 20600p
A.T.Q. -
5x(50) + 9x(25) + 4x(10) = 20600
or, 250x + 225x + 40x = 20600
or, 515x = 20600
or, x = 20600/515
or, x = 40
No. of 50p coins = 5x = 5×40 = 200coins
No. of 25p coins = 9x = 9×40 = 360coins
No. of 10p coins = 4x = 4 × 40 = 160 coins
Answer) No. of 50p coins is 200 , 25p coins
is 360 and 10p coins is 160.
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