Question

A bag contains 6 black and 8 white balls. One ball is drawn at random. What is the probability that the ball drawn is white?
A.43163
B.43197
C.43108
D.43166

Answer 1

$Total \: number \: of \:balls \: in \: a \: bag \\= 6 \: (black ) + 8 \: (white) \\= 14$

$Number \: of \\total \: possible \: outcomes = 14 \: ---(1)$

$Number \:of \: favourable \: outcomes = 8 \:--(2)$

$Probability \: that \: the \: ball \\drawn \:white = \frac{(2)}{(1)} \\= \frac{8}{14}\\= \frac{4}{7}$

Therefore.,

$\red { Required \: probability } \green {= </p><p>\frac{4}{7}}$

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