A bag contains 6 yellow balls, 3 red balls and 2 green balls. In how many ways can 5 balls be drawn from the bag if at least one yellow ball is to be included in the draw?
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In following ways.
The 1st way : 3 red + 1 yellow + 1 green.
The 2nd way : 5 yellow
The 3rd way : 4 yellow + 1 red
The 4th way : 1 y + 3r + 1g
The 5th way : 3y+ 2r
The 6th way : 2y+2g+1r
Hence there r 6 ways
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The 1st way : 3 red + 1 yellow + 1 green.
The 2nd way : 5 yellow
The 3rd way : 4 yellow + 1 red
The 4th way : 1 y + 3r + 1g
The 5th way : 3y+ 2r
The 6th way : 2y+2g+1r
Hence there r 6 ways
Hope u understand
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Hope it helped.
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