In Fig. DEIIBC, AD = 3 cm. AE = 4 cm and BD = 4.5 cm. find CE.
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5
DE II BC
AD/DB=AE/CE (by BPT)
therefore
3/4.5=4/x
x=4*3/2=6
CE= 6cm
thank you
AD/DB=AE/CE (by BPT)
therefore
3/4.5=4/x
x=4*3/2=6
CE= 6cm
thank you
Answered by
4
Answer:
Step-by-step explanation:
Given, DEIIBC
By theorm (If a line drawn parallel to one side of triangle to intersect other two sides in distinct points, the other two sides are divided in the same ratio)
So, AD/BD=AE/EC
3/4.5=4/EC
EC=4*1.5
EC=6cm
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