Question

In Fig. DEIIBC, AD = 3 cm. AE = 4 cm and BD = 4.5 cm. find CE.

Answer 1

DE II BC
AD/DB=AE/CE (by BPT)
therefore
3/4.5=4/x
x=4*3/2=6

CE= 6cm
thank you

Answer 2

Answer:

Step-by-step explanation:

Given, DEIIBC

By theorm (If a line drawn parallel to one side of triangle to intersect other two sides in distinct points, the other two sides are divided in the same ratio)

So, AD/BD=AE/EC

3/4.5=4/EC

EC=4*1.5

EC=6cm