Question

A bag contains 7red,9white,6green and 11black balls if one ball is drawn random,find the probability that it is (1) green (2)not red (3) either white or green

Answer 1

Total no of all possible outcomes=total no of balls
=(7+9+6+11)=33
1)no of green balls =6
:P(getting a green ball)=6/33=2/11
2)total no of not red ball =(9+6+11)=26
:P(getting a ball which is not red)=26/33
3)total no of white and green balls =(9+6)=15
:P(getting v a white or green balls)=15/33=5/11

Answer 2

Total numer of balls= 22
No. of red balls = 7 now P( getting ređ ball ) = 7/22
no. of not red balls= 15
p( gellting ball not rred ) =15/22