Question

pLZ help ... Q.3 and Q.4 ?

Answer 1

in third
apply L hopital
-cosx/-2(π/2-x)
again it is 0/0 form again apply the rule
sinx/(-2(-1))
=1/2.....ans


(4).it is again 0/0 form... so apply the rule as above
-sinx/-1=sinx=1