Question

a bag contains rs 600 in the form of 1 rupee ,50 paise , 25 paise coins in the ratio 3:4:12.find the no. of 25 paise coins

Answer 1

Given the ratio is 3:4:12
let the no of 1rupee coin = 100 paise = 100 × 3x = 300x
50 paise coin = 50 × 4x = 200x
25paise coin = 25 × 12x = 300x
rupees 600 = 60000paise
According to 300x + 200x + 300x = 60000
800x = 60000
x = 75
No. of 25 paise coin = 12 × 75 = 900
So there are 900 coins of 25 paise.

Hope it helps.

Answer 2

$\fontsize{18}{10}{\textup{\textbf{The number of 25 paise coins is 900.}}}$

Step-by-step explanation:

We know that

50 paise = Rs. 0.50  and  25 paise = Rs. 0.25.

Let 3x,  4x and 12x represents the number of 1 rupee coins, 50 paise coins and 25  paise coins respectively.

Then, according to the given information, we have

$3x\times1+4x\times0.50+12x\times0.25=600\\\\\Rightarrow 3x+2x+3x=600\\\\\Rightarrow 8x=600\\\\\Rightarrow x=\dfrac{600}{8}\\\\\Rightarrow x=75.$

Therefore, the number of 25 paise coins is given by

$12x=12\times75=900.$

Thus, required number of 25 paise coins is 900.

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Question : A bag contains rs 600 in the form of one rupee, 50paise and 25 pause coins in the ratio of 3:4:12 . find the total number of 25 pause coins in the bag.

Link : https://brainly.in/question/1230387.