Question

A bag contains rupees 510 in the form of 50 paise,25 paise ande 20 paise coins in the ratio 2:3:4 find the number of coins of each type

Answer 1

LET COINS BE. 2x , 3x , 4x

50paise = 50/100 = rs. 1/2
25paise = 25/100 = rs. 1/4
20paise = 20/100 = rs. 1/5

1/2*2x + 1/4*3x + 1/5*4x = 510
x + 3/4x + 4/5x =510
(20x +15x + 16x)/20 = 510
51x/20 = 510
x = 510*20/51
x = 200
hence ,
coins of 50 paise will be 2x = 2*200 = 400
coins of 25 paise will be 3x = 3*200 = 600
coins of 20 paise will be 4x= 4*200 = 800

Answer 2

Step-by-step explanation:

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