A bag contains some coins of denominations 25 paise, 50 paise and 1, respectively.
The number of 50 paise coins is 5 times the number of 1 coins and number of 25
paise coins is twice the number of 50 paise coins. If the total amount of money in the
bag is 72, find the number of coins of each denomination present in the bag
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Answer:
25 paise coins are 120
50 paise coins are 60
one rupee coins are 12
Explanation:
solve the equation
0.25x+0.5y+z = 72
Given,
y = 5z, x = 2y
where x is no. of 25 paise coins and y is 50 paise coins and z is 1 rupee coins.
after solving we get the answer as x = 120, y = 60, z = 12
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