Question

A bag contains total 14 balls in which 5 are white balls and 9 are red balls. One ball is drawn
from the bag. Find the probability of getting
(a) a white ball
(b) a red ball​

Answer 1

Answer:

probability = favorable outcomes/total outcomes

probability of getting a white ball = 5/14

probability of getting a red ball = 9/14

Answer 2

Step-by-step explanation:

A bag contains 14 balls 5 are white and 9 are red balls one ball is drawn randomly

therefore sample space s={ 1,2,3,4,5,6,7,8,9,10,12,13,14}

n(s)= 14

let A be the first condition that the ball drawn is a white ball

there are 5 white balls

A={ 1,2,3,4,5}

n(A)= 5

therefore p(A)= n(A) divided by n(S)

= 5/14

Let B be the second condition that ball drawn is a red ball

there are 9 red ball

B={1,2,3,4,5,6,7,8,9}

n(B)=9

therefore p(B)=n(B) divided by n(S)

=9/14

probability of ball drawn from the bag getting a white ball is 5/14

and probability of ball drawn from the bag getting a red ball is 9/14