Question

A ball at the end of a 2 meter string revolves in a circle at a rate of 4m/s. What is the centripetal acceleration of the ball

Answer 1

centripetal acceleration =v2/r
v=4,r=2
4*4/2=8 metrepersec2

Answer 2

A ball at the end of a 2 meter string revolves in a circle at a rate of 4m/s. Centripetal acceleration of the ball is

Given:

A ball at the end of a 2 meter string revolves in a circle at a rate of 4m/s.

To find:

Centripetal acceleration of the ball.

Solution:

Generally, the acceleration = (velocity)/(time)

the angular acceleration = (velocity)^2/r

Here the acceleration is equal to the square of velocity upon its radius.

Angular velocity is the time rate at which the object revolves or rotates about an axis.

velocity is directly proportional to distance and inversely proportional to time. and is represented by "V".

Here the centripetal acceleration is the 4 square divided by 2

Then, acceleration = 4^2/2

                               = 16/2

                                = 8 m/s^2.

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