A ball hits a wall horizontly at 6m/s inverse
it rebound horizontly at 4.4m/sms
inverse the ball is contact with the
wall hole 0.040 sec. what is the acche
of the ball
Answers
Answered by
1
Answer:
u =6m/s
v=4.4/s
t =0.04s
a =v-u/t
a =1.6/0.04
a=16/10×100/4
a=40 m/s^2
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