A ball is allowed to fall free from a tower of 320 me when the ball this is Halfway the acceleration suddenly disappears what will happen to the boys thereafter
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The ball will stop according to Newton's 1st law which states that when a body is in motion it tends to be in motion and when a body is in rest it tends to be in rest if any external force is not applied. Here the external force that is gravitational pull is not there
Baidurya:
The ball isn't going to stop at all. It is going to keep on falling
One other person has also answered
he told ball will stop
I also thinks that ball will continue to move with constant speed
That "one other person" is me :-)
and i didn't say for once that the ball is gonna stop
study newtons 1st law
i am not sure about this
you are wrong
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Velocity gained by the ball after it falls freely upto halfway is v = √(u² + 2g.½h) [ball falls halfway]
v=√(0+2×9.8×320/2)m/s [since u=initial velocity=0, as the ball is at rest till the instant it is dropped]
=√(4×49×32)
= 2×7×4√2 = 56√2 m/s
After this, the pull of gravity disappears suddenly. So the ball now falls with a constant speed, without gaining any, due to the lack of any acting force (ignoring resistance offered by air), and thereby due to lack of any acceleration.
v=√(0+2×9.8×320/2)m/s [since u=initial velocity=0, as the ball is at rest till the instant it is dropped]
=√(4×49×32)
= 2×7×4√2 = 56√2 m/s
After this, the pull of gravity disappears suddenly. So the ball now falls with a constant speed, without gaining any, due to the lack of any acting force (ignoring resistance offered by air), and thereby due to lack of any acceleration.
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