Math, asked by ak96087pb4cpq, 1 year ago

dy/dx,if y = ex/sinx

Answers

Answered by Anonymous
6
Solution:-

y = e^x /sinx

diff .with r to x.

dy/dx = (sinx .e^x - e^x .cosx)/ sin^2x

= e^x(sinx -cosx)/sin^2x

shutup1234: okay mr . ransh i ll not
Answered by SidVK
5

 \frac{dy}{dx}  =  \frac{d}{dx} (  \frac{ {e}^{x} }{sinx} )
 \frac{dy}{dx}  =  \frac{ \sin(x)  \frac{d}{dx}  {e}^{x} -  {e}^{x}  \frac{d}{dx} \sin(x)   }{ { \sin }^{2}(x) }
 \frac{dy}{dx }  =   \frac{ \sin(x). {e}^{x} -  {e}^{x}. \cos(x)   }{  { \sin }^{2}(x)  }
 \frac{dy}{dx}  =  \frac{ {e}^{x}( \sin(x)  - \cos(x) )}{ { \sin }^{2}(x) }
Similar questions