Question

a ball is dropped from a height of 10m.if energy of the ball reduces by 40% after striking the ground , how high can the ball bounce back? {g = 10ms-2}

Answer 1

When the ball is dropped from a certain height, it will have some stored gravitational energy. This energy can be shown by 

 GPE = m x g x h

 The potential energy of gravity is directly affected by the height. When the ball is dropped from a 10m height, it loses 40% energy thus affecting the same percentage of height when it bounces back.

Now 40% of the energy lost means 40% of the height also lost on bouncing back. Given height is 10m and when you lose 40% of 10m, left will be 60% of 10m. 

 The height of the bounce back is hence 60% of 10m which 6m.

Answer 2

Answer:

6m

Explanation:

h=10m

g=10m/s^2

Potential energy=mgh=m*10*10

=100*m

Energy reduced = 40%

Energy left=60%

>60% of 100*m

=60/100*100m

=60*m

h=10m

g=10m/s^2

Potential energy=mgh=m*10*10

=100*m

Energy reduced = 40%

Energy left=60%

>60% of 100*m

=60/100*100m

=60*m

60m=mgh

60/g=h

h=10m

g=10m/s^2

Potential energy=mgh=m*10*10

=100*m

Energy reduced = 40%

Energy left=60%

>60% of 100*m

=60/100*100m

=60*m

60m=mgh

60/g=h

h=6metres

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60/g=h

h=6metres

Hope it will help u

Pls mark as brainliest