A ball is dropped from a height platform at equal to zero starting from rest after tea after 6 seconds another ball is thrown downward from the same platform with a speed v the two bones meet at the age of 18 second what is the value of v jesus returns
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Answer:
75m/s
Explanation:
Distance of 1st ball (S)= 1/2 × 10 × 18
= 1620 m
Distance of 2nd ball (S')= ut + 1/2gt^2
1620= 12u +5 × 144
u = 135- 60
=75 m/s
Answered by
1
Answer:75meter per sec
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