Question

A ball is dropped from a height platform at equal to zero starting from rest after tea after 6 seconds another ball is thrown downward from the same platform with a speed v the two bones meet at the age of 18 second what is the value of v jesus returns

Answer 1

Answer:

75m/s

Explanation:

Distance of 1st ball (S)= 1/2 × 10 × 18

= 1620 m

Distance of 2nd ball (S')= ut + 1/2gt^2

1620= 12u +5 × 144

u = 135- 60

=75 m/s

Answer 2

Answer:75meter per sec

Explanation: