Physics, asked by VINEET6920, 11 months ago

A ball is dropped from the such nights at distance travelled in lost again is equal to distance travelled in first 3 seconds

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Answered by sopumaan100
3

The total distance covered by it in the last second of its motion is equal to the distance covered by it in first three second. ⇒ total distance traveled in 1st 3 seconds of the motion = distance traveled in last 1 second. ∴ Let the total time taken to drop from height 'h' to ground be t,.

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