A ball is dropped from the such nights at distance travelled in lost again is equal to distance travelled in first 3 seconds
Answers
Answered by
3
The total distance covered by it in the last second of its motion is equal to the distance covered by it in first three second. ⇒ total distance traveled in 1st 3 seconds of the motion = distance traveled in last 1 second. ∴ Let the total time taken to drop from height 'h' to ground be t,.
Similar questions