Question

a ball is droppedfrom a bridge 122.5m above a river . after 2sec a second ball is thrown down it . what must its initial velicity​

Answer 1

Answer:

26.133 m/s

Time taken by first ball to hit water can be found as

s= ut + ½ gt2

122.5 = ½ * 9.8 * t2

t2= 25

t =5

Now the next ball must cover this distance in 3 s to hit water at same time.

122.5 = 3 u + ½ * 9.8 * 32

122.5 = 3u + 44.1

3u = 78.4

u= 26.133 m/s

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