Question

a ball is just dropped from height of 100m if its velocity increases uniformly at the rate of 10m per second . What is the velocity of the ball with which it strikes to the ground ? What is the time taken by ball to reach at the ground (Step by step explanation and Quickly please)​

Answer 1

Answer:

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Answer 2

Let us assume, the final velocity with which the ball will strike the ground be ‘v’ and the time it takes to strike the ground be ‘t’.

Given parameters

• Initial Velocity of the ball (u) = 0
• Distance or height of fall (s) = 20 m
• Downward acceleration (a) = 10 m $s^{-2}$

As we know

$\sf \: 2as = {v}^{2} - {u}^{2}$

$\longrightarrow\sf \: v^2 = 2as + u^2$

$\longrightarrow\sf v^2 = (2 \times 10 \times 20 ) + 0$

$\longrightarrow\sf v^2 = 400$

Final velocity of ball (v) = 20 ms-1

$\sf \: t = \frac{(v – u)}{a}$

Time taken by the ball to strike

$\sf(t) = \frac{ (20 – 0)}{10}$

$\leadsto \sf \: t = \cancel \frac{20}{10}$

$\leadsto \sf \: t = 2 \: seconds$

The final velocity with which the ball will strike the ground is (v) = 20 ms-1

The time it takes to strike the ground (t) = 2 seconds