Question

A ball is projected from a point at a distance 100 m
from a building. The ball enters a window,
horizontally, at a height of 50 m. Find the magnitude
and direction of velocity of projection.​

Answer 1

Answer:

The answer is 50√2 m/s

Explanation:

Hope it helps. Please mark as brainliest. ._.

Answer 2

The answer is 50√2 m/s in downward direction.

GIVEN

A ball is projected from a point at a distance 100 m

from a building. The ball enters a window,

horizontally, at a height of 50 m

TO FIND

The magnitude and velocity of projection

SOLUTION

The above problem can be simplybsolved as follows;

Height of the projectile, = u²sin²θ/2g

Where,

u = initial velocity

g = acceleration due to gravity

tanθ = 50/100

= 1/2

h = √(1)² + (4)

h = √5

sinθ = 1/√5

Now,

20 × 50 = u² (1/√5)²

u² = 20 × 50 × 5

u = √(20 × 50 × 5)

= 50√2 m/s

Hence, The answer is 50√2 m/s in downward direction.

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