Question

A bullet of mass m1 moving with velocity v strikes a block of mass m2 at rest and gets embedded into it. The
kinetic energy of the composite block will be
a)

$\frac{1}{2} m {v}^{2} \frac{m2}{m1 + m2}$
b)
$\frac{1}{2} {m1}^{2} \frac{m2}{m1 + m2}$
​

Answer 1

Explanation:

according to...

conservation of the momentum

v'=(m1v) /m1+m2

kinetic energy

= 1/2m(v)^2

=1/2(m1+m2)[(m1v) /m1+m2]^2

=1/2(m1v) ^2/m1+m2

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