Question

A ball is projected with velocity u at right angle to the slope which inclined at an angle alpha with the horizontal. The distance x along the inclined plane that it will travell before again striking the slope is-

Answer 1

Answer:

Displacement of the object along the inclined plane is given as

$x = \frac{2u^2 sin\alpha}{g cos^2\alpha}$

Explanation:

As we know that ball is projected perpendicular to the inclined plane

Now the acceleration perpendicular to the inclined plane is given as

$a_y = - gcos\alpha$

now we can find the time of flight of the object

$T = \frac{2u}{gcos\alpha}$

now we can find the displacement along the inclined plane by using the kinematics equation along the plane

$x = \frac{1}{2}a_x t^2$

$x = \frac{1}{2}(g sin\alpha)(\frac{2u}{g cos\alpha})^2$

$x = \frac{2u^2 sin\alpha}{g cos^2\alpha}$

#Learn

Topic : Projectile motion

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