Question

A ball is released from a height of 1 metre. What time it will take to reach the surface
the earth ? Ans:0.45 s
​

Answer 1

Answer:

Hi...

it is 0.1 seconds

see,distance -1m

speed or velocity of the object -10m/s

time =d/speed

time =1m/10m/s

time =0.1 seconds.

I hope it will help you

Step-by-step explanation:

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Answer 2

It will take 0.45 seconds

Step-by-step explanation:

Since, the height of the ball,

$h=ut+\frac{1}{2}gt^2$

Where,

u = initial velocity of ball,

g is gravitational acceleration having value 9.8 m/s²,

t = time taken to reach the surface of earth,

Here, h = 1 meter, u = 0 m/s,

$1=\frac{1}{2}\times 9.8t^2$

$1=4.9t^2$

$t^2 =\frac{1}{4.9}$

$\implies t \approx 0.45$

Hence, it will take 0.45 seconds ( approx )

#Learn more :

A cricket ball of mass 90 g moving with a velocity of 0.5 m/s is stopped by a player  in 0.45 s. What is the force applied by the player to stop the ball?​

https://brainly.in/question/11355573