Question

A ball is released from the top of the tower of height H metres it takes t seconds to reach the ground what is the position of the ball in T/3 seconds​

Answer 1

Explanation:

height of tower = h

time taken = t

for freely falling body u = 0

so h = (0)

t+2

1

gt 2

h= 2

1

gt 2

t 2

g

2h

at

3

t

s

s=(0)t+

2

1

g(

3

t

)

2

s=

2

1

g

9

(t

2

)

s=

18

g

×

g

2h

s=

9

h