Question

a ball is thrown at 40 m/s with angle of projection of 30° with the horizontal the vertical component of the velocity of projectile after 1 sec will be
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Answer 1

Given : θ=30

o

u=40m/s

Vertical component of velocity at the time of throwing u

v

=u sin30

o

=40×0.5=20m/s (upward)

Thus vertical component of velocity just before the ball strikes the ground V=u

v

=20m/s