A ball is thrown at a speed of 40 m/s at an angle of 60° with the horizontal. Find (a) the maximum height reached and (b) the range of the ball. Take g = 10 m/s2.
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Explanation:
(a) the maximum height reached H = 40²sin²60°/20 = 60 m.
(b) the range of the ball = 40²sin120°/10 = 80√3 m
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