A ball is thrown from a point on ground at some angle of projection. At the same time a bird starts from a point directly above this point of projection at a height h horizontally with speed u. Given that in its flight ball just touches the bird at one point. Find the distance on ground where ball strikes
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v cos θ = u
h = u^2 sin 2θ/ 2g
v sin θ= √2gh
R = (2usinθ ucosθ)/g
= 2√(2gh) u/g
=2u√(2h/g)
h = u^2 sin 2θ/ 2g
v sin θ= √2gh
R = (2usinθ ucosθ)/g
= 2√(2gh) u/g
=2u√(2h/g)
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