Question

A ball is thrown from the roof of a building of height 44m with speed v, at an angle below the
horizontal. It lands 2 seconds later at a point 30m from the base of the building, then the value of
tan theta is: (g = 10 m/s2)​

Answer 1

Answer:

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Answer 2

Answer:

tan theta = 4/5

Step-by-step explanation:

it is making an angle theta below the horizontal so

horizontal velocity = V cos theta

vertical velocity = v sin theta

acc to question

44 = v sin theta (2) + 1/2 (10)(2^2)

12 = v sin theta -----(1)

and

v cos theta (2) = 30

or

15 = v cos theta ----(2)

dividing (1) and (2)

tan theta = 4/5