Question

A ball is thrown horizontally at a speed of 3.0 m/s from the window of a building 6.5 m high. How far from the base of the building does the ball strike the ground?

Answer 1

Answer:

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Explanation:

If we look at just the Y direction (vertical), then we have a displacement of -50m (since we start at the roof and go down), an initial velocity of 0, and an acceleration of -9.8 m/s2. We can use our equations of motion to say that y = v0t + 1/2 at2. Now we can say:

-50 = 0 + 1/2(-9.8)t2

50 = 4.9t2

10.2 = t2

3.19 seconds = t

So we know that the ball takes 3.19 seconds to hit the ground.

Now we can look at the X (horizontal) direction to see how far it goes in 3.19 seconds

X = v0t + 1/2at2

There is no acceleration in the x direction, so a = 0

X = 20(3.19) + 0

Multiply those and you'll see how far it goes in the horizontal direction