Question

A ball is thrown up from ground with a speed of 40 m/s. Distance travelled by the particle and its velocity at the end of 5s is: answer fast

Answer 1

Explanation:

u=40m/s

t=5s

a= -9.8m/s^2

Now,

s=ut-1/2at^2

s=40×5-1/2×9.8×25

s=200-122.5

s=77.5 m

Again,

v=u-at

v=40-9.8×5

v=-9m/s