Question

A ball is thrown up under gravity (g = 10m/sec). Find its
velocity after 1.0 sec at a height of 10m [MP PMT 2010]​

Answer 1

Given: g=10m/s^2

t=1 sec,. h=10m

To find :v=?

We have, h = ut- (1/2)gt^2

10 = ux1-5

Therefore, u =15m/sec

Answer 2

Answer:5m/sec

Explanation:First we will find the initial velocity

h = ut - 1/2gt^2 [h=10m; g=10m/sec^2; t=1sec]

10 = u-5

u = 15

Now, we can substitute the value of u in v = u - gt and find final velocity

v = 15 - 10(1)

v = 5m/sec