A ball is thrown upward with a speed of 10/s .calculate the speed of the ball after 1 second..(answer it honestly!!)
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Answer:
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Explanation:
Using the equation v = u + at, where ‘v’ is final velocity (what we want to calculate), ‘u’ is the initial velocity (10 m/s in this case), ‘a’ is acceleration (because the ball is being thrown up, acceleration due to gravity will be -9.8 m/s^2), and ‘t’ is the time (in this occasion it’s since the ball was thrown).
So plugging the numbers into the equation:
v = 10 + (-9.8)*(1)
v = 10 - 9.8
v = 0.2 m/s
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ball thrown upward with speed = 10 second
calculate the speed of the ball after = 1 second
So , the answer is =10 Second
- 1 Second
___________
09 Second
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