Question

A ball is thrown upward with a speed of 15 ms 1 . find the distance travelled by the ball is 2 second. Take g= 9.8ms-2​

Answer 1

Answer:

S=10.4m

Explanation:

u=15m/s

t=2sec

g=9.8m/s2

s=ut+1/2at^2

s=15(2)+1/2(-9.8)(4)

s=30-19.6

s=10.4 m

Answer 2

$\huge{\underline{\pink{\tt{Given,}}}}$

• The Initial Velocity (u) with Which the ball is thrown up - 15m/s
• The Time (t) with Which the Distance travelled by the ball - 2 Second
• Acceleration Due to Gravity (g) - 9.8 m/s²

$\huge{\underline{\pink{\tt{To \ Find,}}}}$

• The Distance Travelled by the ball in two Second.

$\huge{\underline{\pink{\tt{Solution :}}}}$

$\longrightarrow$ We know this Equation :

$\bigstar \boxed{\sf{\orange{s = ut - \dfrac{1}{2}gt^{2}}}}$

║Here,

• s = Distance
• u = Initial Velocity
• t = Time
• g = Acceleration Due to Gravity ║

Now Put the Value in this Equation :

$\mapsto \sf{ s = ut - \dfrac{1}{2}gt^{2}}$

$\mapsto \sf{s = 15(2) - \dfrac{1}{2} (9.8)(2)^{2}}$

$\mapsto \sf{s = 30 - \dfrac{1}{2} (9.8)(4)}$

$\mapsto \sf{s = 30 - 19.6}$

$\mapsto \boxed{\sf{s = 10.4 m}}$

$\rule{200}2$