Question

a ball is thrown upwards with a velocity of 20m per sec .how high the ball go taking g=9.8m per sec

Answer 1

Heya!!!

Here is your answer.

Given :
u = 20 m/s
v = 0 (as the ball will stop)
g = -10 m/s² (as the ball is thrown up)

Using third equation of motion,
2gs = v² - u²
2 × -10s = - (20)²
s = 400/20
s = 20 m.

Hope it helps

Answer 2

Hi.

v2=u2−2gs

When the object reached its peak it will have zero speed or velocity. Hence the final velocity is 0.

v=0

u=20

0=(20)2−2(10)s

s=20m

We can now see the time the object is at its peak

v=u+at

0=20–10t

t=2s...



Hope this helps u!!